3.1 \(\int (c+d x)^4 \sinh (a+b x) \, dx\)

Optimal. Leaf size=91 \[ -\frac{24 d^3 (c+d x) \sinh (a+b x)}{b^4}+\frac{12 d^2 (c+d x)^2 \cosh (a+b x)}{b^3}-\frac{4 d (c+d x)^3 \sinh (a+b x)}{b^2}+\frac{24 d^4 \cosh (a+b x)}{b^5}+\frac{(c+d x)^4 \cosh (a+b x)}{b} \]

[Out]

(24*d^4*Cosh[a + b*x])/b^5 + (12*d^2*(c + d*x)^2*Cosh[a + b*x])/b^3 + ((c + d*x)^4*Cosh[a + b*x])/b - (24*d^3*
(c + d*x)*Sinh[a + b*x])/b^4 - (4*d*(c + d*x)^3*Sinh[a + b*x])/b^2

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Rubi [A]  time = 0.120453, antiderivative size = 91, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 2, integrand size = 14, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.143, Rules used = {3296, 2638} \[ -\frac{24 d^3 (c+d x) \sinh (a+b x)}{b^4}+\frac{12 d^2 (c+d x)^2 \cosh (a+b x)}{b^3}-\frac{4 d (c+d x)^3 \sinh (a+b x)}{b^2}+\frac{24 d^4 \cosh (a+b x)}{b^5}+\frac{(c+d x)^4 \cosh (a+b x)}{b} \]

Antiderivative was successfully verified.

[In]

Int[(c + d*x)^4*Sinh[a + b*x],x]

[Out]

(24*d^4*Cosh[a + b*x])/b^5 + (12*d^2*(c + d*x)^2*Cosh[a + b*x])/b^3 + ((c + d*x)^4*Cosh[a + b*x])/b - (24*d^3*
(c + d*x)*Sinh[a + b*x])/b^4 - (4*d*(c + d*x)^3*Sinh[a + b*x])/b^2

Rule 3296

Int[((c_.) + (d_.)*(x_))^(m_.)*sin[(e_.) + (f_.)*(x_)], x_Symbol] :> -Simp[((c + d*x)^m*Cos[e + f*x])/f, x] +
Dist[(d*m)/f, Int[(c + d*x)^(m - 1)*Cos[e + f*x], x], x] /; FreeQ[{c, d, e, f}, x] && GtQ[m, 0]

Rule 2638

Int[sin[(c_.) + (d_.)*(x_)], x_Symbol] :> -Simp[Cos[c + d*x]/d, x] /; FreeQ[{c, d}, x]

Rubi steps

\begin{align*} \int (c+d x)^4 \sinh (a+b x) \, dx &=\frac{(c+d x)^4 \cosh (a+b x)}{b}-\frac{(4 d) \int (c+d x)^3 \cosh (a+b x) \, dx}{b}\\ &=\frac{(c+d x)^4 \cosh (a+b x)}{b}-\frac{4 d (c+d x)^3 \sinh (a+b x)}{b^2}+\frac{\left (12 d^2\right ) \int (c+d x)^2 \sinh (a+b x) \, dx}{b^2}\\ &=\frac{12 d^2 (c+d x)^2 \cosh (a+b x)}{b^3}+\frac{(c+d x)^4 \cosh (a+b x)}{b}-\frac{4 d (c+d x)^3 \sinh (a+b x)}{b^2}-\frac{\left (24 d^3\right ) \int (c+d x) \cosh (a+b x) \, dx}{b^3}\\ &=\frac{12 d^2 (c+d x)^2 \cosh (a+b x)}{b^3}+\frac{(c+d x)^4 \cosh (a+b x)}{b}-\frac{24 d^3 (c+d x) \sinh (a+b x)}{b^4}-\frac{4 d (c+d x)^3 \sinh (a+b x)}{b^2}+\frac{\left (24 d^4\right ) \int \sinh (a+b x) \, dx}{b^4}\\ &=\frac{24 d^4 \cosh (a+b x)}{b^5}+\frac{12 d^2 (c+d x)^2 \cosh (a+b x)}{b^3}+\frac{(c+d x)^4 \cosh (a+b x)}{b}-\frac{24 d^3 (c+d x) \sinh (a+b x)}{b^4}-\frac{4 d (c+d x)^3 \sinh (a+b x)}{b^2}\\ \end{align*}

Mathematica [A]  time = 0.347484, size = 76, normalized size = 0.84 \[ \frac{\cosh (a+b x) \left (12 b^2 d^2 (c+d x)^2+b^4 (c+d x)^4+24 d^4\right )-4 b d (c+d x) \sinh (a+b x) \left (b^2 (c+d x)^2+6 d^2\right )}{b^5} \]

Antiderivative was successfully verified.

[In]

Integrate[(c + d*x)^4*Sinh[a + b*x],x]

[Out]

((24*d^4 + 12*b^2*d^2*(c + d*x)^2 + b^4*(c + d*x)^4)*Cosh[a + b*x] - 4*b*d*(c + d*x)*(6*d^2 + b^2*(c + d*x)^2)
*Sinh[a + b*x])/b^5

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Maple [B]  time = 0.033, size = 547, normalized size = 6. \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((d*x+c)^4*sinh(b*x+a),x)

[Out]

1/b*(c^4*cosh(b*x+a)+1/b^4*d^4*((b*x+a)^4*cosh(b*x+a)-4*(b*x+a)^3*sinh(b*x+a)+12*(b*x+a)^2*cosh(b*x+a)-24*(b*x
+a)*sinh(b*x+a)+24*cosh(b*x+a))+1/b^4*d^4*a^4*cosh(b*x+a)-4/b^4*d^4*a*((b*x+a)^3*cosh(b*x+a)-3*(b*x+a)^2*sinh(
b*x+a)+6*(b*x+a)*cosh(b*x+a)-6*sinh(b*x+a))+4/b^3*d^3*c*((b*x+a)^3*cosh(b*x+a)-3*(b*x+a)^2*sinh(b*x+a)+6*(b*x+
a)*cosh(b*x+a)-6*sinh(b*x+a))+6/b^4*d^4*a^2*((b*x+a)^2*cosh(b*x+a)-2*(b*x+a)*sinh(b*x+a)+2*cosh(b*x+a))+6/b^2*
d^2*c^2*((b*x+a)^2*cosh(b*x+a)-2*(b*x+a)*sinh(b*x+a)+2*cosh(b*x+a))-4/b^4*d^4*a^3*((b*x+a)*cosh(b*x+a)-sinh(b*
x+a))+4/b*d*c^3*((b*x+a)*cosh(b*x+a)-sinh(b*x+a))-4/b^3*d^3*a^3*c*cosh(b*x+a)+6/b^2*d^2*a^2*c^2*cosh(b*x+a)-4/
b*d*a*c^3*cosh(b*x+a)-12/b^3*d^3*a*c*((b*x+a)^2*cosh(b*x+a)-2*(b*x+a)*sinh(b*x+a)+2*cosh(b*x+a))+12/b^3*d^3*a^
2*c*((b*x+a)*cosh(b*x+a)-sinh(b*x+a))-12/b^2*d^2*a*c^2*((b*x+a)*cosh(b*x+a)-sinh(b*x+a)))

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Maxima [B]  time = 1.1229, size = 440, normalized size = 4.84 \begin{align*} \frac{c^{4} e^{\left (b x + a\right )}}{2 \, b} + \frac{2 \,{\left (b x e^{a} - e^{a}\right )} c^{3} d e^{\left (b x\right )}}{b^{2}} + \frac{c^{4} e^{\left (-b x - a\right )}}{2 \, b} + \frac{2 \,{\left (b x + 1\right )} c^{3} d e^{\left (-b x - a\right )}}{b^{2}} + \frac{3 \,{\left (b^{2} x^{2} e^{a} - 2 \, b x e^{a} + 2 \, e^{a}\right )} c^{2} d^{2} e^{\left (b x\right )}}{b^{3}} + \frac{3 \,{\left (b^{2} x^{2} + 2 \, b x + 2\right )} c^{2} d^{2} e^{\left (-b x - a\right )}}{b^{3}} + \frac{2 \,{\left (b^{3} x^{3} e^{a} - 3 \, b^{2} x^{2} e^{a} + 6 \, b x e^{a} - 6 \, e^{a}\right )} c d^{3} e^{\left (b x\right )}}{b^{4}} + \frac{2 \,{\left (b^{3} x^{3} + 3 \, b^{2} x^{2} + 6 \, b x + 6\right )} c d^{3} e^{\left (-b x - a\right )}}{b^{4}} + \frac{{\left (b^{4} x^{4} e^{a} - 4 \, b^{3} x^{3} e^{a} + 12 \, b^{2} x^{2} e^{a} - 24 \, b x e^{a} + 24 \, e^{a}\right )} d^{4} e^{\left (b x\right )}}{2 \, b^{5}} + \frac{{\left (b^{4} x^{4} + 4 \, b^{3} x^{3} + 12 \, b^{2} x^{2} + 24 \, b x + 24\right )} d^{4} e^{\left (-b x - a\right )}}{2 \, b^{5}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*x+c)^4*sinh(b*x+a),x, algorithm="maxima")

[Out]

1/2*c^4*e^(b*x + a)/b + 2*(b*x*e^a - e^a)*c^3*d*e^(b*x)/b^2 + 1/2*c^4*e^(-b*x - a)/b + 2*(b*x + 1)*c^3*d*e^(-b
*x - a)/b^2 + 3*(b^2*x^2*e^a - 2*b*x*e^a + 2*e^a)*c^2*d^2*e^(b*x)/b^3 + 3*(b^2*x^2 + 2*b*x + 2)*c^2*d^2*e^(-b*
x - a)/b^3 + 2*(b^3*x^3*e^a - 3*b^2*x^2*e^a + 6*b*x*e^a - 6*e^a)*c*d^3*e^(b*x)/b^4 + 2*(b^3*x^3 + 3*b^2*x^2 +
6*b*x + 6)*c*d^3*e^(-b*x - a)/b^4 + 1/2*(b^4*x^4*e^a - 4*b^3*x^3*e^a + 12*b^2*x^2*e^a - 24*b*x*e^a + 24*e^a)*d
^4*e^(b*x)/b^5 + 1/2*(b^4*x^4 + 4*b^3*x^3 + 12*b^2*x^2 + 24*b*x + 24)*d^4*e^(-b*x - a)/b^5

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Fricas [A]  time = 2.59911, size = 350, normalized size = 3.85 \begin{align*} \frac{{\left (b^{4} d^{4} x^{4} + 4 \, b^{4} c d^{3} x^{3} + b^{4} c^{4} + 12 \, b^{2} c^{2} d^{2} + 24 \, d^{4} + 6 \,{\left (b^{4} c^{2} d^{2} + 2 \, b^{2} d^{4}\right )} x^{2} + 4 \,{\left (b^{4} c^{3} d + 6 \, b^{2} c d^{3}\right )} x\right )} \cosh \left (b x + a\right ) - 4 \,{\left (b^{3} d^{4} x^{3} + 3 \, b^{3} c d^{3} x^{2} + b^{3} c^{3} d + 6 \, b c d^{3} + 3 \,{\left (b^{3} c^{2} d^{2} + 2 \, b d^{4}\right )} x\right )} \sinh \left (b x + a\right )}{b^{5}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*x+c)^4*sinh(b*x+a),x, algorithm="fricas")

[Out]

((b^4*d^4*x^4 + 4*b^4*c*d^3*x^3 + b^4*c^4 + 12*b^2*c^2*d^2 + 24*d^4 + 6*(b^4*c^2*d^2 + 2*b^2*d^4)*x^2 + 4*(b^4
*c^3*d + 6*b^2*c*d^3)*x)*cosh(b*x + a) - 4*(b^3*d^4*x^3 + 3*b^3*c*d^3*x^2 + b^3*c^3*d + 6*b*c*d^3 + 3*(b^3*c^2
*d^2 + 2*b*d^4)*x)*sinh(b*x + a))/b^5

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Sympy [A]  time = 3.23735, size = 311, normalized size = 3.42 \begin{align*} \begin{cases} \frac{c^{4} \cosh{\left (a + b x \right )}}{b} + \frac{4 c^{3} d x \cosh{\left (a + b x \right )}}{b} + \frac{6 c^{2} d^{2} x^{2} \cosh{\left (a + b x \right )}}{b} + \frac{4 c d^{3} x^{3} \cosh{\left (a + b x \right )}}{b} + \frac{d^{4} x^{4} \cosh{\left (a + b x \right )}}{b} - \frac{4 c^{3} d \sinh{\left (a + b x \right )}}{b^{2}} - \frac{12 c^{2} d^{2} x \sinh{\left (a + b x \right )}}{b^{2}} - \frac{12 c d^{3} x^{2} \sinh{\left (a + b x \right )}}{b^{2}} - \frac{4 d^{4} x^{3} \sinh{\left (a + b x \right )}}{b^{2}} + \frac{12 c^{2} d^{2} \cosh{\left (a + b x \right )}}{b^{3}} + \frac{24 c d^{3} x \cosh{\left (a + b x \right )}}{b^{3}} + \frac{12 d^{4} x^{2} \cosh{\left (a + b x \right )}}{b^{3}} - \frac{24 c d^{3} \sinh{\left (a + b x \right )}}{b^{4}} - \frac{24 d^{4} x \sinh{\left (a + b x \right )}}{b^{4}} + \frac{24 d^{4} \cosh{\left (a + b x \right )}}{b^{5}} & \text{for}\: b \neq 0 \\\left (c^{4} x + 2 c^{3} d x^{2} + 2 c^{2} d^{2} x^{3} + c d^{3} x^{4} + \frac{d^{4} x^{5}}{5}\right ) \sinh{\left (a \right )} & \text{otherwise} \end{cases} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*x+c)**4*sinh(b*x+a),x)

[Out]

Piecewise((c**4*cosh(a + b*x)/b + 4*c**3*d*x*cosh(a + b*x)/b + 6*c**2*d**2*x**2*cosh(a + b*x)/b + 4*c*d**3*x**
3*cosh(a + b*x)/b + d**4*x**4*cosh(a + b*x)/b - 4*c**3*d*sinh(a + b*x)/b**2 - 12*c**2*d**2*x*sinh(a + b*x)/b**
2 - 12*c*d**3*x**2*sinh(a + b*x)/b**2 - 4*d**4*x**3*sinh(a + b*x)/b**2 + 12*c**2*d**2*cosh(a + b*x)/b**3 + 24*
c*d**3*x*cosh(a + b*x)/b**3 + 12*d**4*x**2*cosh(a + b*x)/b**3 - 24*c*d**3*sinh(a + b*x)/b**4 - 24*d**4*x*sinh(
a + b*x)/b**4 + 24*d**4*cosh(a + b*x)/b**5, Ne(b, 0)), ((c**4*x + 2*c**3*d*x**2 + 2*c**2*d**2*x**3 + c*d**3*x*
*4 + d**4*x**5/5)*sinh(a), True))

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Giac [B]  time = 1.16781, size = 437, normalized size = 4.8 \begin{align*} \frac{{\left (b^{4} d^{4} x^{4} + 4 \, b^{4} c d^{3} x^{3} + 6 \, b^{4} c^{2} d^{2} x^{2} - 4 \, b^{3} d^{4} x^{3} + 4 \, b^{4} c^{3} d x - 12 \, b^{3} c d^{3} x^{2} + b^{4} c^{4} - 12 \, b^{3} c^{2} d^{2} x + 12 \, b^{2} d^{4} x^{2} - 4 \, b^{3} c^{3} d + 24 \, b^{2} c d^{3} x + 12 \, b^{2} c^{2} d^{2} - 24 \, b d^{4} x - 24 \, b c d^{3} + 24 \, d^{4}\right )} e^{\left (b x + a\right )}}{2 \, b^{5}} + \frac{{\left (b^{4} d^{4} x^{4} + 4 \, b^{4} c d^{3} x^{3} + 6 \, b^{4} c^{2} d^{2} x^{2} + 4 \, b^{3} d^{4} x^{3} + 4 \, b^{4} c^{3} d x + 12 \, b^{3} c d^{3} x^{2} + b^{4} c^{4} + 12 \, b^{3} c^{2} d^{2} x + 12 \, b^{2} d^{4} x^{2} + 4 \, b^{3} c^{3} d + 24 \, b^{2} c d^{3} x + 12 \, b^{2} c^{2} d^{2} + 24 \, b d^{4} x + 24 \, b c d^{3} + 24 \, d^{4}\right )} e^{\left (-b x - a\right )}}{2 \, b^{5}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d*x+c)^4*sinh(b*x+a),x, algorithm="giac")

[Out]

1/2*(b^4*d^4*x^4 + 4*b^4*c*d^3*x^3 + 6*b^4*c^2*d^2*x^2 - 4*b^3*d^4*x^3 + 4*b^4*c^3*d*x - 12*b^3*c*d^3*x^2 + b^
4*c^4 - 12*b^3*c^2*d^2*x + 12*b^2*d^4*x^2 - 4*b^3*c^3*d + 24*b^2*c*d^3*x + 12*b^2*c^2*d^2 - 24*b*d^4*x - 24*b*
c*d^3 + 24*d^4)*e^(b*x + a)/b^5 + 1/2*(b^4*d^4*x^4 + 4*b^4*c*d^3*x^3 + 6*b^4*c^2*d^2*x^2 + 4*b^3*d^4*x^3 + 4*b
^4*c^3*d*x + 12*b^3*c*d^3*x^2 + b^4*c^4 + 12*b^3*c^2*d^2*x + 12*b^2*d^4*x^2 + 4*b^3*c^3*d + 24*b^2*c*d^3*x + 1
2*b^2*c^2*d^2 + 24*b*d^4*x + 24*b*c*d^3 + 24*d^4)*e^(-b*x - a)/b^5